(8x^2)+22x+9=0

Solution for (8x^2)+22x+9=0 equation:

(8x^2)+22x+9=0

a = 8; b = 22; c = +9;
Δ = b2-4ac
Δ = 222-4·8·9
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-14}{2*8}=\frac{-36}{16}
=-2+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+14}{2*8}=\frac{-8}{16}
=-1/2
$